Yêu cầu:
Tính tích các giá trị dương trên 1 cột ma trận số thực
Thuật toán:
1. Viết hàm nhập vào ma trận
2. Viết hàm tính tích các giá trị dương trên 1 cột ma trận số thực
Code:
/*****Product of positive elements in column of matrix******** *Author: vncoding *Date : 31/03/2019 ************************************************************/ #include <stdio.h> #include <conio.h> #include <stdlib.h> #define N 100 #define M 100 void ImportData(float[][M], int, int, char*); void PrintMatrix(float[][M], int, int); float ProductColInMatrix(float[][M], int, int, int); void main() { int nRow, nCol; int iCol; float A[N][M]; printf("\nNumber of row: "); scanf("%d", &nRow); printf("\nNumber of column: "); scanf("%d", &nCol); do { printf("\nNumber of specified column: "); scanf("%d", &iCol); } while (iCol <= 0 || iCol > nRow); ImportData(A, nRow, nCol, "A"); PrintMatrix(A, nRow, nCol); printf("\nProduct of positive elements in column (%d) matrix: %f", iCol, ProductColInMatrix(A, nRow, nCol, iCol)); getch(); } /************************************************************* * Function : ProductColInMatrix() * Parameter : A[][M]: input matrix (I) nRow : row number (I) nCol : column number(I) specCol : specified column(I) * Return : int * Description : Product of positive elements in column of matrix *************************************************************/ float ProductColInMatrix(float A[][M], int nRow, int nCol, int specCol) { int iRow, iCol; float product = 1.0; for (iRow = 0; iRow < nRow; iRow++) { for (iCol = 0; iCol < nCol; iCol++) { if (((iCol + 1) == specCol) && A[iRow][iCol] > 0) product *= A[iRow][iCol]; } } return product; } /************************************************************* * Function : ImportData() * Parameter : A[][M]: input matrix (I) nRow : row number (I) nCol : column number(I) nameMatrix: matrix name (I) * Return : void * Description : Import matrix data *************************************************************/ void ImportData(float Matrix[][M], int nRow, int nCol, char* nameMatrix) { int iRow, iCol; for (iRow = 0; iRow < nRow; iRow++) for (iCol = 0; iCol < nCol; iCol++) { printf("\n%s[%d][%d] = ", nameMatrix, iRow, iCol); scanf("%f", &Matrix[iRow][iCol]); } } /************************************************************* * Function : PrintMatrix() * Parameter : Matrix: input matrix (I) nRow : row number (I) nCol : column number(I) * Return : void * Description : Display matrix data *************************************************************/ void PrintMatrix(float Matrix[][M], int nRow, int nCol) { int iRow, iCol; printf("\nA = "); for (iRow = 0; iRow < nRow; iRow++) { printf("\n"); for (iCol = 0; iCol < nCol; iCol++) { printf("\t%.2f\t", Matrix[iRow][iCol]); } } }
Kết quả:
Number of row: 3
Number of column: 4
Number of specified column: 2
A[0][0] = -2
A[0][1] = -3.4
A[0][2] = 3.4
A[0][3] = 5.6
A[1][0] = 3.4
A[1][1] = 21
A[1][2] = -3.5
A[1][3] = 3.4
A[2][0] = 12.3
A[2][1] = 5.6
A[2][2] = 7.6
A[2][3] = 7.8
A =
-2.00 -3.40 3.40 5.60
3.40 21.00 -3.50 3.40
12.30 5.60 7.60 7.80
Product of positive elements in column (2) matrix: 117.599998
Leave a Reply
You must be logged in to post a comment.